2[10(x+2)-4(5+2.5x)]=0

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Solution for 2[10(x+2)-4(5+2.5x)]=0 equation:


Simplifying
2[10(x + 2) + -4(5 + 2.5x)] = 0

Reorder the terms:
2[10(2 + x) + -4(5 + 2.5x)] = 0
2[(2 * 10 + x * 10) + -4(5 + 2.5x)] = 0
2[(20 + 10x) + -4(5 + 2.5x)] = 0
2[20 + 10x + (5 * -4 + 2.5x * -4)] = 0
2[20 + 10x + (-20 + -10x)] = 0

Reorder the terms:
2[20 + -20 + 10x + -10x] = 0

Combine like terms: 20 + -20 = 0
2[0 + 10x + -10x] = 0
2[10x + -10x] = 0

Combine like terms: 10x + -10x = 0
2[0] = 0

Multiply 2 * 0
0 = 0

Anything times zero is zero.
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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